document.write( "Question 775609: If a boy walks from his house to school at 4 km/h, he reaches the school 10 minutes earlier than the scheduled time. However if he walks the rate of 3 km/h he reaches 10 minutes late. The distance of the school from his house is \n" ); document.write( "
Algebra.Com's Answer #473013 by josgarithmetic(39617)\"\" \"About 
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The required time to make his trip is x, in hours. When he is early using 4 km/hour, time is x-1/6. When he is late at 3 km/hour time is x+1/6. Whether early or late, the trip is the same distance. \r
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\n" ); document.write( "\n" ); document.write( "Traveling to school, rate*time=distance
\n" ); document.write( "10 minutes = 1/6 hour
\n" ); document.write( "Early: \"4%28x-1%2F6%29\"
\n" ); document.write( "Late: \"3%28x%2B1%2F6%29\"
\n" ); document.write( "Equal Distance: \"highlight%284%28x-1%2F6%29=3%28x%2B1%2F6%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4x-2%2F3=3x%2B1%2F2\"
\n" ); document.write( "\"x-2%2F3=1%2F2\"
\n" ); document.write( "\"x=1%2F2%2B2%2F3=%283%2B4%29%2F6=highlight%287%2F6%29\" hours
\n" ); document.write( "\"x=1%261%2F6\" hour
\n" ); document.write( "1 hour 10 minutes if he were to be \"on-time\".\r
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\n" ); document.write( "\n" ); document.write( "HOW FAR FROM HOME TO SCHOOL?
\n" ); document.write( "Pick either early or late expression and compute the value.
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