document.write( "Question 775528: My problem is something is wrong with the equation. The instruction says to correct the equation to make it work. Could you help me?\r
\n" ); document.write( "\n" ); document.write( "The original equation is r+s/r+t = 1 + s/t\r
\n" ); document.write( "\n" ); document.write( "Could you show me the correct equation, then assign values to r,s, and t. I need to show that the equation is correct by substituting in values.
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Algebra.Com's Answer #472979 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The original equation is r+s/r+t = 1 + s/t
\n" ); document.write( ":
\n" ); document.write( "\"%28%28r%2Bs%29%29%2F%28%28r%2Bt%29%29\" = 1 + \"s%2Ft\"
\n" ); document.write( "change it to
\n" ); document.write( "\"%28%28r%2Bs%29%29%2F%28%28r%2Bt%29%29\" = 1 - \"s%2Ft\"
\n" ); document.write( "Assign values: r=1, t=2; find s
\n" ); document.write( "\"%28%281%2Bs%29%29%2F%28%281%2B2%29%29\" = 1 - \"s%2F2\"
\n" ); document.write( "\"%28%281%2Bs%29%29%2F%283%29\" = 1 - \"s%2F2\"
\n" ); document.write( "multiply equation by 6
\n" ); document.write( "2(1+s) = 6 - 3s
\n" ); document.write( "2 + 2s = 6 - 3s
\n" ); document.write( "2s + 3s = 6 - 2
\n" ); document.write( "5s = 4
\n" ); document.write( "s = 4/5
\n" ); document.write( "s = .8
\n" ); document.write( ":
\n" ); document.write( "See if r=1; s=.8; t=2 works in the original equation
\n" ); document.write( "\"%28%281%2B.8%29%29%2F%28%281%2B2%29%29\" = 1 + \".8%2F2\"
\n" ); document.write( "\"1.8%2F3\" = 1 - .4
\n" ); document.write( ".6 = .6, our equation works now
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