document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=775416>Question 775416</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 4 times the first number and three times the second number is 15. The difference of three times the first number and twice the second number is 7. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #472923 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=472923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x + 3y = 15...1<BR>\n" );
document.write( "3x - 2y = 7....2<BR>\n" );
document.write( "Multiply (1) by 2<BR>\n" );
document.write( "Multiply (2) by 3<BR>\n" );
document.write( "8x + 6y = 30...3<BR>\n" );
document.write( "9x - 6y = 21...4<BR>\n" );
document.write( "Add (3) + (4)<BR>\n" );
document.write( "17x     = 51<BR>\n" );
document.write( "x       = 3<BR>\n" );
document.write( "Substitute x = 3 into (1)<BR>\n" );
document.write( "4x + 3y = 15<BR>\n" );
document.write( "12 + 3y = 15<BR>\n" );
document.write( "     3y = 15 - 12<BR>\n" );
document.write( "     3y = 3<BR>\n" );
document.write( "      y = 1<BR>\n" );
document.write( "numbers are 3 and 1<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );