document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=775429>Question 775429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 84 meters. The length is 6 meters longer than twice the width. find he dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #472851 by </B><A HREF=/tutors/aboutme.mpl?userid=sofiyac><B>sofiyac(983)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sofiyac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sofiyac><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=472851\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the width be x, then the length is 2x+6<BR>\n" );
document.write( "perimeter is all sides added together so<BR>\n" );
document.write( "x+x+2x+6+2x+6=84 solve for x<BR>\n" );
document.write( "6x+12=84 subtract 12 from each side of the equal sign<BR>\n" );
document.write( "6x=72 divide each side by 6<BR>\n" );
document.write( "x=12 so width is 12 now plug that back into what we said length was in the first sentence, so length=2x+6=2*12+6=24+6=30<BR>\n" );
document.write( "width 12, length 30 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );