document.write( "Question 775422: A number, half of that number, and one third of that number are added. the result is 22. What is the original number?
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Algebra.Com's Answer #472847 by sofiyac(983) $\"\"$ $\"About$

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let the number be x, then
\n" ); document.write( "x+x/2+x/3=22 solve for x, common denominator would be 6, so
\n" ); document.write( " $\"6x%2F6%2B3x%2F6%2B2x%2F6=22\"$ now that all the x terms have common denominator we can combine them...add the tops, leave the bottom
\n" ); document.write( " $\"%286x%2B3x%2B2x%29%2F6=22\"$
\n" ); document.write( " $\"11x%2F6=22\"$ now multiply each side by the reverse of what's in front of x, so by 6/11, this will give you x by itself
\n" ); document.write( " $\"x=22%2A%286%2F11%29\"$ you can reduce top and bottom by 11 (ie 22/11=2 and 11/11=1)
\n" ); document.write( " $\"x=2%2A6\"$
\n" ); document.write( " $\"x=12\"$ \n" ); document.write( "

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