document.write( "Question 775353: Ram can do a piece of work in 8 days while shyam alone can do in 12 days. Ram starts doing the work and they work at it alternately for a day. In how many days will the work be finished? \n" ); document.write( "
Algebra.Com's Answer #472793 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Each day Ram works he does 1/8 of the piece of work\r\n" ); document.write( "Each day Shyam works she does 1/12 of the piece of work.\r\n" ); document.write( "\r\n" ); document.write( "Get common denominator:\r\n" ); document.write( "\r\n" ); document.write( "1/8 = 3/24\r\n" ); document.write( "1/12 = 2/24\r\n" ); document.write( "\r\n" ); document.write( "Day 1: 3/24 of work is done.\r\n" ); document.write( "Day 2: 3/24 + 2/24 = 5/24 of work is done.\r\n" ); document.write( "Day 3: 5/24 + 3/24 = 8/24 of work is done\r\n" ); document.write( "Day 4: 8/24 + 2/24 = 10/24 = 5/12 of work is done \r\n" ); document.write( "Day 5: 10/24 + 3/24 = 13/24 of work is done\r\n" ); document.write( "Day 6: 13/24 + 2/24 = 15/24 = 5/8 of work is done\r\n" ); document.write( "Day 7: 15/24 + 3/24 = 18/24 = 3/4 of work is done\r\n" ); document.write( "Day 8: 18/24 + 2/24 = 20/24 = 5/6 of work is done\r\n" ); document.write( "Day 9: 20/24 + 3/24 = 23/24 of work is done\r\n" ); document.write( "Day 10: Since there is only 1/24 of the work left to do,\r\n" ); document.write( "Shyam only works half a day.\r\n" ); document.write( "\r\n" ); document.write( "Answer: Ram works on days 1,3,5,7,9 or 5 full days \r\n" ); document.write( " Shyam works on days 2,4,6,8, and half a day on \r\n" ); document.write( " day 10, or\n" ); document.write( " |