document.write( "Question 775232: At 3PM a plane leaves London to fly to Madrid at 1260 km away. At 4PM, a second plane leaves Madrid to fly to London going 40 km faster than the first plane. The two planes pass each other at 4:30 PM. What is the speed of each plane? \n" ); document.write( "
Algebra.Com's Answer #472776 by mananth(16946)\"\" \"About 
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At 3PM a plane leaves London to fly to Madrid at 1260 km away. At 4PM, a second plane leaves Madrid to fly to London going 40 km faster than the first plane. The two planes pass each other at 4:30 PM. What is the speed of each plane?\r
\n" ); document.write( "\n" ); document.write( "Speed of London Madrid plane =x\r
\n" ); document.write( "\n" ); document.write( "starts at3 PM
\n" ); document.write( "meets oncoming plane at 4.30 PM
\n" ); document.write( "time = traveled = 1.5 hours.
\n" ); document.write( "distance traveled = 1.5x
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "speed of Madrid London plane = x+ 40 km/h\r
\n" ); document.write( "\n" ); document.write( "It leaves 1 hour late
\n" ); document.write( "So it meets the oncoming plane in 1/2 hour\r
\n" ); document.write( "\n" ); document.write( "distance traveled = 0.5*(x+40)\r
\n" ); document.write( "\n" ); document.write( "1.5x+0.5x+20=1260\r
\n" ); document.write( "\n" ); document.write( "2x=1240
\n" ); document.write( "x=620 km/h speed of London Madrid plane\r
\n" ); document.write( "\n" ); document.write( "620+40 = 660 km/h speed of Madrid London Plane\r
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