document.write( "Question 775322: Write the linear equation: perpendicular to x-3y=7 through (6,2). Thank you. :) \n" ); document.write( "
Algebra.Com's Answer #472770 by mananth(16946)\"\" \"About 
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1 x + -3 y = 7
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "-3 y = -1 x + 7
\n" ); document.write( "Divide by -3
\n" ); document.write( " y = 1/ 3 x + -2 1/3
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = 1/3
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal -3
\n" ); document.write( "Because m1*m2 =-1
\n" ); document.write( "The slope of the required line will be -3
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\n" ); document.write( "m= -3 ,point ( 6 , 2 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "2 = -18 + b
\n" ); document.write( "b= 20
\n" ); document.write( "m= -3
\n" ); document.write( "The required equation is y = -3 x + 20
\n" ); document.write( "m.ananth@hotmail.ca
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