document.write( "Question 775153: I have no idea how to do this!!! please help!!!:
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Algebra.Com's Answer #472696 by Edwin McCravy(20081)\"\" \"About 
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I have no idea how to do this!!! please help!!!:
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document.write( "When you have a rectangle problem, always start out by drawing the rectangle.\r\n" );
document.write( "We start with this rectangle. Label the width as W and the length as 2W.\r\n" );
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document.write( "Its area is (LENGTH)·(WIDTH) = (2W)·(W) = 2W²\r\n" );
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document.write( "We cut off the part in green below which is 3 centimeters chopped off \r\n" );
document.write( "the 2W length, making the length of the shorter black regtangle 2W-3\r\n" );
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document.write( "The resulting rectangle's area = (LENGTH)·(WIDTH) = (2W-3)·(W) = 2W²-3W\r\n" );
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document.write( "We are told that the area of the resulting rectangle is 12 square \r\n" );
document.write( "centimeters less than the original rectangle.\r\n" );
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document.write( "Area of resulting rectangle = Area of original rectangle - 12 square \r\n" );
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document.write( "           2W²-3W = 2W² - 12\r\n" );
document.write( "              -3W = -12\r\n" );
document.write( "                W = 4 centimeters.\r\n" );
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document.write( "That's the width of both rectangles, since we did not change that.\r\n" );
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document.write( "The length of the original rectangle is 2W or 2(4) = 8 centimeters.\r\n" );
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document.write( "So you can see the actual square centimeters I will draw in the square\r\n" );
document.write( "centimeters and you can see the 12 green square centimeters of area\r\n" );
document.write( "that were cut off.\r\n" );
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document.write( "Edwin
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