document.write( "Question 775107: i need help solving the equation graphically and then checking the results algebraially \"x%5E2-3x=10\" \n" ); document.write( "
Algebra.Com's Answer #472667 by sofiyac(983)\"\" \"About 
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\n" ); document.write( "\"x%5E2-3x=10\"
\n" ); document.write( "\"x%5E2-3x=10\" first subtract 10 from each side of the equal sign
\n" ); document.write( "\"x%5E2-3x-10=0\" next pretend instead of 0 on the right side you have y
\n" ); document.write( "\"x%5E2-3x-10=y\" plug in a few values for x (any values) and evaluate, this will give you the matching y's. Here's the table
\n" ); document.write( "x | y
\n" ); document.write( "________
\n" ); document.write( "0 | -10
\n" ); document.write( "-2| 0
\n" ); document.write( "5 | 0
\n" ); document.write( "feel free to do more points, you need quite a few to graph a quadratic but you get the point.
\n" ); document.write( "Now plot these points
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2-3x-10%29+\"
\n" ); document.write( "As you can see from the graph it crosses x axis at 5 and -2
\n" ); document.write( "Now to check the results plug in the solution one at a time
\n" ); document.write( "check for x=5
\n" ); document.write( "\"x%5E2-3x=10\"
\n" ); document.write( "\"5%5E2-3%2A5=10\"
\n" ); document.write( "\"25-15=10\"
\n" ); document.write( "\"10=10\" left side equals right side so x=5 is a solution
\n" ); document.write( "check for x=-2
\n" ); document.write( "\"%28-2%29%5E2-3%28-2%29=10\"
\n" ); document.write( "\"4%2B6=10\"
\n" ); document.write( "\"10=10\" left side equals right side so x=-2 is a solution
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