document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=775086>Question 775086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x + 4 = –3x + 14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #472637 by </B><A HREF=/tutors/aboutme.mpl?userid=ContraPangloss><B>ContraPangloss(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ContraPangloss><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=472637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We want to get the x by itself, so we can start by subtracting 4 from both sides to get\r<BR>\n" );
document.write( "\n" );
document.write( "2x = -3x + 10\r<BR>\n" );
document.write( "\n" );
document.write( "Then, add 3x to both sides to get\r<BR>\n" );
document.write( "\n" );
document.write( "5x = 10\r<BR>\n" );
document.write( "\n" );
document.write( "Divide both sides by 5 to get x= 2\r<BR>\n" );
document.write( "\n" );
document.write( "For this type of problem, just think about what you can do to get x alone, starting with the easiest thing first. As long as you do everything to both sides of the equation, you are set! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );