document.write( "Question 66608: Here is my question:\r
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\n" ); document.write( "\n" ); document.write( "6 - sqrt of 20
\n" ); document.write( "-------------- = ?????
\n" ); document.write( " 2\r
\n" ); document.write( "\n" ); document.write( "I came up with 6 - sqrt of 5. I am not sure if this is correct. I need someone to let me know if I am doing this stuff correctly, please.
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Algebra.Com's Answer #47263 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Here is my question: \r
\n" ); document.write( "\n" ); document.write( "6 - sqrt of 20
\n" ); document.write( "-------------- = ?????
\n" ); document.write( "2
\n" ); document.write( "I came up with 6 - sqrt of 5. I am not sure if this is correct. I need someone to let me know if I am doing this stuff correctly, please.\r
\n" ); document.write( "\n" ); document.write( "YOU ARE ON THE RIGHT TRACK!!!!!!!!!!!!!!! YOU MUST HAVE FORGOTTEN TO ALSO DIVIDE 6 BY 2\r
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\n" ); document.write( "\n" ); document.write( "(6-sqrt(20))/2 this equals\r
\n" ); document.write( "\n" ); document.write( "(6-sqrt(4)(5))/2 and this equals\r
\n" ); document.write( "\n" ); document.write( "(6-2sqrt5)/2 which equals\r
\n" ); document.write( "\n" ); document.write( "6/2-(2sqrt5)/2= and this reduces to:\r
\n" ); document.write( "\n" ); document.write( "3-sqrt5\r
\n" ); document.write( "\n" ); document.write( "ck by using a calculator\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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