document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66609>Question 66609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The period of a pendulum (T) is the amount of time in seconds it takes the pendulum to make a complete swing back and forth.  The period is determined by the formula\r<BR>\n" );
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document.write( "Pendulum Formula\r<BR>\n" );
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document.write( "where l is the length of the pendulum in meters. \r<BR>\n" );
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document.write( "pendulum image\r<BR>\n" );
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document.write( "Question: \r<BR>\n" );
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document.write( "Find the length of the pendulum with a period of 6 s.  Express your answer to the nearest tenth.  (Use pi = 3.14) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47262 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47262\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The period of a pendulum (T) is the amount of time in seconds it takes the pendulum to make a complete swing back and forth. The period is determined by the formula <BR>\n" );
document.write( "Pendulum Formula <BR>\n" );
document.write( "where l is the length of the pendulum in meters. <BR>\n" );
document.write( "pendulum image <BR>\n" );
document.write( "Question: <BR>\n" );
document.write( "Find the length of the pendulum with a period of 6 s. Express your answer to the nearest tenth. (Use pi = 3.14)\r<BR>\n" );
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document.write( "Pendulum Formula:  T=2pi(sqrt(l/g))  Want to solve for l: square both sides:\r<BR>\n" );
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document.write( "T^2=4(pi^2)(l/g)  Multiply both sides by g\r<BR>\n" );
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document.write( "(T^2)(g)=4(pi^2)(l)  divide both sides by 4(pi^2)\r<BR>\n" );
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document.write( "((T^2)(g))/(4(pi^2))=l now we plug in the values:\r<BR>\n" );
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document.write( "NOTE:  g=9.8m/(sec^2)\r<BR>\n" );
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document.write( "l=((6^2)(9.8))/(39.44)=\r<BR>\n" );
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document.write( "l=((36)(sec^2)(9.8)m/(sec^2))/39.44\r<BR>\n" );
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document.write( "l=8.9 meters\r<BR>\n" );
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document.write( "Actually, you can solve this by plugging in the values without solving for l\r<BR>\n" );
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document.write( "T=2pi(sqrt(l)/sqrt(g))<BR>\n" );
document.write( "6=6.28(sqrt(l)/3.13   Note:  call it 3.14\r<BR>\n" );
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document.write( "6=2sqrt(l)<BR>\n" );
document.write( "3=sqrt(l)     square both sides\r<BR>\n" );
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document.write( "l=9 meters\r<BR>\n" );
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document.write( "ck by using a calculator\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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