document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=774745>Question 774745</A>: <I><SPAN STYLE=\"word-break: break-all;\"> johns garden is twice as long as it is wide. if the perimeter of the garden is 42 feet what is an equation to find the width of the garden </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #472572 by </B><A HREF=/tutors/aboutme.mpl?userid=arKed><B>arKed(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=arKed><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=arKed><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=472572\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 42<BR>\n" );
document.write( "2W + 2L = P<BR>\n" );
document.write( "where L = 2W\r<BR>\n" );
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document.write( "2W + 2 (2W) = P<BR>\n" );
document.write( "2W +4W = P<BR>\n" );
document.write( "6W / 6 = 42 / 6<BR>\n" );
document.write( "W = 7.....ANS.\r<BR>\n" );
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document.write( "AL' SOL'N :\r<BR>\n" );
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document.write( "2W = P - 2L<BR>\n" );
document.write( "2W = 42 - 2 (2W)<BR>\n" );
document.write( "2W / 2= (42 - 2 (W))/ 2<BR>\n" );
document.write( "W = 21 - 2W<BR>\n" );
document.write( "3W /3 = 21 / 3<BR>\n" );
document.write( "W = 7.....ANS. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );