document.write( "Question 774903: how to make 20 liters of 25 percent acidic solution into 40 percent acidic solution. \n" ); document.write( "

Algebra.Com's Answer #472571 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = liters of pure acid to be added
\n" ); document.write( " $\"+.25%2A20+=+5+\"$ liters of acid in 25% solution
\n" ); document.write( "-----------------
\n" ); document.write( " $\"+%28+5+%2B+x+%29+%2F+%28+20+%2B+x+%29+=+.4+\"$
\n" ); document.write( " $\"+5+%2B+x+=+.4%2A%28+20+%2B+x+%29+\"$
\n" ); document.write( " $\"+5+%2B+x+=+8+%2B+.4x+\"$
\n" ); document.write( " $\"+.6x+=+8+-+5+\"$
\n" ); document.write( " $\"+.6x+=+3+\"$
\n" ); document.write( " $\"+x+=+5+\"$
\n" ); document.write( "5 liters of pure acid need to be added
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+5+%2B+x+%29+%2F+%28+20+%2B+x+%29+=+.4+\"$
\n" ); document.write( " $\"+%28+5+%2B+5+%29+%2F+%28+20+%2B+5+%29+=+.4+\"$
\n" ); document.write( " $\"+10+%2F+25+=+.4+\"$
\n" ); document.write( " $\"+10+=+.4%2A25+\"$
\n" ); document.write( " $\"+10+=+10+\"$
\n" ); document.write( "OK \n" ); document.write( "

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