document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=774924>Question 774924</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man who can row 4 miles per hour in still water finds that it requires 6 1/2 hours to row upstream a distance requiring 3 1/4 to row downstream. what is the rate of the stream?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #472508 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=472508\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This type of uniform rates problem comes up so frequently that a more general solution is valuable.  \r<BR>\n" );
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document.write( "A man can row R miles per hour in still water needs g hours to row upsteam for distance d and requires b hours to row that same distance back downsteam.  Find the rate of the stream, c.\r<BR>\n" );
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document.write( "R = row rate in still water.<BR>\n" );
document.write( "c = rate of stream.<BR>\n" );
document.write( "g = time to travel d distance upstream.<BR>\n" );
document.write( "b = time to travel d distance downstream.<BR>\n" );
document.write( "d = each one-way distance up and back destination.<BR>\n" );
document.write( "INQUIRY FOR UNKNOWN VARIABLE, c.<BR>\n" );
document.write( "INTERMEDIATE UNKNOWN VARIABLE, d.\r<BR>\n" );
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document.write( "ORGANIZE DATA INTO TABLE\r<BR>\n" );
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document.write( "Direction_______rate_________time__________distance<BR>\n" );
document.write( "Up______________R-c__________g_____________d=(R-c)g<BR>\n" );
document.write( "Back____________R+c__________b_____________d=(R+c)b\r<BR>\n" );
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document.write( "The distance going up to the destination, upstream is equal to the distance returning back downstream.  In this general case, observe that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R-c%3CR%2Bc ALIGN=MIDDLE  ALT=\"R-c%3CR%2Bc\"   DISABLED_style= \"max-width:90%; height:auto;\" > and that this is in agreement with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=g%3Eb ALIGN=MIDDLE  ALT=\"g%3Eb\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "The equality of the two distances indicates <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28%28R-c%29g=%28R%2Bc%29b%29 ALIGN=MIDDLE  ALT=\"highlight%28%28R-c%29g=%28R%2Bc%29b%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "We solve this equation for the unknown number, c. </SPAN>\n" );
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