document.write( "Question 774882: I am just having trouble figuring out exactly where to start I have gotten a little ways a couple of different tries. 7x+2 is over 14x-3 and likewise on the other side of the equation. I have tried multiplying both sides by the 2x+3 denominator. Then I have all of these variables on the left and only x-8 on the right. I am having trouble making sense of this. I feel like I am close I just need a bit of a nudge. Thanks
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document.write( "7x + 2 = x – 8
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document.write( "14x – 3 2x+3
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Algebra.Com's Answer #472501 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply by (14x-3)(2x+3) on both sides\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we get\r \n" ); document.write( "\n" ); document.write( "(7x+2)(2x+3)=(x-8)((14x-3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "14x^2 cancel off\r \n" ); document.write( "\n" ); document.write( "25x+6=-115x+24\r \n" ); document.write( "\n" ); document.write( "140x=20\r \n" ); document.write( "\n" ); document.write( "/140 \n" ); document.write( "x=20/140 \n" ); document.write( "x=1/7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |