document.write( "Question 774156: Q: The measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure.\r
\n" ); document.write( "\n" ); document.write( "I know that the answer is 51 degrees but how do I get there. (This is for my algebra II class)
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Algebra.Com's Answer #472483 by MathTherapy(10559)\"\" \"About 
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\n" ); document.write( "Q: The measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure.\r
\n" ); document.write( "\n" ); document.write( "I know that the answer is 51 degrees but how do I get there. (This is for my algebra II class)\r
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\n" ); document.write( "\n" ); document.write( "Let angle be A\r
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\n" ); document.write( "\n" ); document.write( "Then its supplement = 180 - A, and its complement = 90 - A\r
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\n" ); document.write( "\n" ); document.write( "Therefore, 180 - A = 3(90 - A) + 12\r
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\n" ); document.write( "\n" ); document.write( "180 - A = 270 - 3A + 12 \r
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\n" ); document.write( "\n" ); document.write( "180 - A = 282 - 3A\r
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\n" ); document.write( "\n" ); document.write( "- A + 3A = 282 - 180\r
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\n" ); document.write( "\n" ); document.write( "2A = 102\r
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\n" ); document.write( "\n" ); document.write( "A, or angle = \"102%2F2\", or \"highlight_green%2851%5Eo%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can do the check!! \r
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\n" ); document.write( "\n" ); document.write( "Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com
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