document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=774156>Question 774156</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Q: The measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure.\r<BR>\n" );
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document.write( "I know that the answer is 51 degrees but how do I get there. (This is for my algebra II class) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #472482 by </B><A HREF=/tutors/aboutme.mpl?userid=arKed><B>arKed(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=arKed><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=arKed><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=472482\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n1 + n2 = 180<BR>\n" );
document.write( "n2 = 12 + 3(n1)<BR>\n" );
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document.write( "n1 + n2 = 180<BR>\n" );
document.write( "n1 + 12 + 3n1 = 180<BR>\n" );
document.write( "4n1 + 12 = 180<BR>\n" );
document.write( "4n1 = 180 - 12<BR>\n" );
document.write( "4n1 = 168<BR>\n" );
document.write( "4n1 / 4 = 168 / 4<BR>\n" );
document.write( "n1 = 42 degrees ans.\r<BR>\n" );
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document.write( "n2 = 12 + (42)<BR>\n" );
document.write( "n2 = 138 degrees ans.\r<BR>\n" );
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document.write( "checking:\r<BR>\n" );
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document.write( "n1 + n2 = 180<BR>\n" );
document.write( "42 + 138 = 180<BR>\n" );
document.write( "180 = 180 </SPAN>\n" );
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