document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=774814>Question 774814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm having trouble with this equation: (x-5)/2 + (1/2)=2x-(x-3)/8<BR>\n" );
document.write( "I kind of remember this from algebra 1 but not quite. Don't I have to multiply everything by the common denominator? I'm confused. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #472479 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=472479\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm having trouble with this equation: (x-5)/2 + (1/2)=2x-(x-3)/8<BR>\n" );
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document.write( "first let's put the numerators on either side of the = over a common denominator<BR>\n" );
document.write( "(x-5+1) / 2  =  (16x - (x-3)) /8 <BR>\n" );
document.write( "(x-4) / 2  = (15x + 3) / 8<BR>\n" );
document.write( "now cross multiply the fractions<BR>\n" );
document.write( "8x -32 = 30x +6\r<BR>\n" );
document.write( "\n" );
document.write( "-22x = 38<BR>\n" );
document.write( "x = -38/22<BR>\n" );
document.write( "x = -19/11<BR>\n" );
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