document.write( "Question 66495This question is from textbook Advanced mathematics
\n" ); document.write( ": log4^2 + log4^8 = log4^(x+3) \n" ); document.write( "

Algebra.Com's Answer #47243 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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log4^2 + log4^8 = log4^(x+3)
\n" ); document.write( ":
\n" ); document.write( "When you have logs of the same number you can just add the exponents,
\n" ); document.write( "you can write it:
\n" ); document.write( "log 4^(2+8)) = log 4^(x+3)
\n" ); document.write( " log 4^10 = log 4^(x+3)
\n" ); document.write( ":
\n" ); document.write( "from this we can see that:
\n" ); document.write( "10 = x+3
\n" ); document.write( "x = 7
\n" ); document.write( ":
\n" ); document.write( "Check it by substitution:
\n" ); document.write( "log 4^2 + log 4^8 = log 4^(7+3)
\n" ); document.write( "log 4^2 + log 4^8 = log 4^10 \n" ); document.write( "

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