document.write( "Question 773821: how to graph and identify the focus, directrix, and axis of symmetry of x=-y^2
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Algebra.Com's Answer #472421 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! how to graph and identify the focus, directrix, and axis of symmetry of x=-y^2 \n" ); document.write( "*** \n" ); document.write( "Given equation is that of a parabola which opens leftward. \n" ); document.write( "Its basic form: (y-k)^2=-4p(x-h), (h,k)=(x,y) coordinates of the vertex. \n" ); document.write( ".. \n" ); document.write( "y^2=-x \n" ); document.write( "vertex: (0,0) \n" ); document.write( "axis of symmetry: y=0 \n" ); document.write( "4p=1 \n" ); document.write( "p=1/4 \n" ); document.write( "focus: (-1/4,0) (p distance to left of vertex on the axis of symmetry) \n" ); document.write( "directrix: x=1/4 (p distance to right of vertex on the axis of symmetry) \n" ); document.write( "see graph below: \n" ); document.write( " |