document.write( "Question 774694: I am having trouble telling if the equation has one, two, or no solutions: \"x%5E2-15x%2B56=0\" \n" ); document.write( "
Algebra.Com's Answer #472379 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2-15x%2B56=0\"....first factor completely so we can use zero product rule; write \"-15x\" as \"-7x-8x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-7x-8x%2B56+=+0\"......group\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-7x%29-%288x-56+%29=+0\"...factor\r
\n" ); document.write( "\n" ); document.write( "\"x%28x-7%29-8%28x-7+%29=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-8%29%28x-7%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if \"%28x-8%29+=+0\", then \"x=8\"\r
\n" ); document.write( "\n" ); document.write( "if \"%28x-7%29+=+0\", then \"x=7\"\r
\n" ); document.write( "\n" ); document.write( "so, you have two real solutions\r
\n" ); document.write( "\n" ); document.write( "let's see them on a graph\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-2%2C+15%2C+-2%2C+10%2C+x%5E2-15x%2B56%29+\"\r
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