document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=774590>Question 774590</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this question:\r<BR>\n" );
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document.write( "the length of rectangle is twice as much as its breadth. if the perimeter is 120cm, the length of the rectangle is   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #472326 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=472326\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length of rectangle is twice as much as its breadth. if the perimeter is 120cm, the length of the rectangle is:<BR>\n" );
document.write( "let x=breadth of rectangle<BR>\n" );
document.write( "2x=length of rectangle<BR>\n" );
document.write( "twice the breadth+twice the length=perimeter<BR>\n" );
document.write( "2x+4x=120<BR>\n" );
document.write( "6x=120<BR>\n" );
document.write( "x=20<BR>\n" );
document.write( "2x=40<BR>\n" );
document.write( "the length of the rectangle is: 40 cm </SPAN>\n" );
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