document.write( "Question 774554: Find three consecutive integers such three times the third integer added to one half of the first integer is 14 less than twice the second integer. \n" ); document.write( "

Algebra.Com's Answer #472307 by algebrahouse.com(1659) $\"\"$ $\"About$

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x = first
\n" ); document.write( "x + 1 = second {consecutive integers increase by 1 each time}
\n" ); document.write( "x + 2 = third\r
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\n" ); document.write( "\n" ); document.write( "3(x + 2) + 0.5x = 2(x + 1) - 14 {three times the third added to half the first is 14 less than twice the second}
\n" ); document.write( "3x + 6 + 0.5x = 2x + 2 - 14 {used distributive property}
\n" ); document.write( "3.5x + 6 = 2x - 12 {combined like terms}
\n" ); document.write( "1.5x = -18 {subtracted 2x and 6 from each side}
\n" ); document.write( "x = -12 {divided each side by 1.5}
\n" ); document.write( "x + 1 = -11 {substituted -12, in for x, into x + 1}
\n" ); document.write( "x + 2 = -10 {substituted -12, in for x, into x + 2}\r
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\n" ); document.write( "\n" ); document.write( "-12, -11, and -10 are the three consecutive integers
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