document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66582>Question 66582</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A jeweler is using 10 lbs. of an alloy that is 2% robium.  He has another alloy which is 5% robium.  He wishes to combine these mixtures to form a mixture that is 3% robium.  How many pounds of the second alloy should be added to the first to get a mixture that is 3% robium.\r<BR>\n" );
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document.write( "I really need help, so I would ask for step by step instructions please.\r<BR>\n" );
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document.write( "Thank you.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47229 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47229\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A jeweler is using 10 lbs. of an alloy that is 2% robium. He has another alloy which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium. How many pounds of the second alloy should be added to the first to get a mixture that is 3% robium. <BR>\n" );
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document.write( "2% alloy DATA:<BR>\n" );
document.write( "Amount = 10 lbs ; amount of robium= 0.02(10)=0.2 lbs<BR>\n" );
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document.write( "5% alloy DATA:<BR>\n" );
document.write( "Amount= x lbs ; amount of robium=0.05x lbs.<BR>\n" );
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document.write( "Mixture DATA:<BR>\n" );
document.write( "Amount = x+10 lbs ; amount of robium = 0.3(x+10)=(0.03x+0.3) lbs<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "robium + robium = robium<BR>\n" );
document.write( "0.2 +0.05x = 0.03x+0.3<BR>\n" );
document.write( "0.02x=0.1<BR>\n" );
document.write( "x=5 lbs (amount of 5% alloy that must be added)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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