document.write( "Question 774491: Port and Starboard are paddling canoes. They travel 20 miles downstream in 4 hrs. They return upstream in 6 hrs.
\n" ); document.write( "A. How fast is the current?
\n" ); document.write( "B. How fast can they paddle in still water?
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Algebra.Com's Answer #472272 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+c+\" = the speed of the current
\n" ); document.write( "Let \"+s+\" = their speed paddling in still water
\n" ); document.write( "--------------
\n" ); document.write( "Equation for going downstream:
\n" ); document.write( "(1) \"+20+=+%28+s+%2B+c+%29%2A4+\"
\n" ); document.write( "Equation for going upstream:
\n" ); document.write( "(2) \"+20+=+%28+s+-+c+%29%2A6+\"
\n" ); document.write( "--------------------
\n" ); document.write( "(1) \"+4s+%2B+4c+=+20+\"
\n" ); document.write( "(1) \"+s+%2B+c+=+5+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+6s+-+6c+=+20+\"
\n" ); document.write( "(2) \"+3s+-+3c+=+10+\"
\n" ); document.write( "------------------
\n" ); document.write( "Multiply both sides of (1) by \"+3+\"
\n" ); document.write( "and add the equations
\n" ); document.write( "(2) \"+3s+-+3c+=+10+\"
\n" ); document.write( "(1) \"+3s+%2B+3c+=+15+\"
\n" ); document.write( "\"+6s+=+25+\"
\n" ); document.write( "\"+s+=+4.167+\" mi/hr
\n" ); document.write( "and
\n" ); document.write( "(1) \"+s+%2B+c+=+5+\"
\n" ); document.write( "(1) \"+4.167+%2B+c+=+5+\"
\n" ); document.write( "(1) \"+c+=+.833+\" mi/hr
\n" ); document.write( "--------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+20+=+%28+s+%2B+c+%29%2A4+\"
\n" ); document.write( "(1) \"+20+=+%28+4.167+%2B+.833+%29%2A4+\"
\n" ); document.write( "(1) \"+20+=+5%2A4+\"
\n" ); document.write( "(1) \"+20+=+20+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+20+=+%28+s+-+c+%29%2A6+\"
\n" ); document.write( "(2) \"+20+=+%28+4.167+-+.833+%29%2A6+\"
\n" ); document.write( "(2) \"+20+=+3.333%2A6+\"
\n" ); document.write( "(2) \"+20+=+20+\"
\n" ); document.write( "OK
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