document.write( "Question 774396: each of my five digits is one more than the digit to its left.the sum of my digits is 20.what number am i ? \n" ); document.write( "
Algebra.Com's Answer #472266 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! each of my five digits is one more than the digit to its left.the sum of my digits is 20.what number am i ?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let ten-thousands digit be T \n" ); document.write( "Then thousands digit = T + 1 \n" ); document.write( "Hundreds digit = T + 1 + 1, or T + 2 \n" ); document.write( "Tens digit = T + 2 + 1, or T + 3 \n" ); document.write( "Units digit = T + 3 + 1, or T + 4 \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "Therefore, T + T + 1 + T + 2 + T + 3 + T + 4 = 20 \n" ); document.write( "5T + 10 = 20 \n" ); document.write( "5T = 20 – 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "T, or tens-thousands digit = \n" ); document.write( "Thousands digit = 2 + 1, or 3 \n" ); document.write( "Hundreds digit = 3 + 1, or 4 \n" ); document.write( "Tens digit = 4 + 1, or 5 \n" ); document.write( "Units digit = 5 + 1, or 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Five-digit number: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "OR Solve using the sum of an arithmetic series: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can do the check!! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com \n" ); document.write( " |