document.write( "Question 774175: The Johnson family has three sons, Billy, Tommy and Bobby. Billy is as old as Tommy and Bobby together. Last year, Tommy was twice as old as Bobby was. In two years, Billy will be twice as old as Tommy is now. How old is each son? \n" ); document.write( "
Algebra.Com's Answer #472112 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! The Johnson family has three sons, Billy, Tommy and Bobby. Billy is as old as Tommy and Bobby together. Last year, Tommy was twice as old as Bobby was. In two years, Billy will be twice as old as Tommy is now. How old is each son? \n" ); document.write( "*** \n" ); document.write( "let x=tommy's present age \n" ); document.write( "let y=bobby's present age \n" ); document.write( "x+y=billy's present age \n" ); document.write( ".. \n" ); document.write( "last year: \n" ); document.write( " x-1=tommy's age \n" ); document.write( " y-1=bobby's age \n" ); document.write( "x+y-1=billy's age \n" ); document.write( "tommy was twice as old bobby \n" ); document.write( "x-1=2(y-1) \n" ); document.write( ".. \n" ); document.write( "in 2 years: \n" ); document.write( "x+2=tommy's age \n" ); document.write( " y+2=bobby's age \n" ); document.write( "x+y+2=billy's age \n" ); document.write( "Billy will be twice as old as Tommy is now. \n" ); document.write( "x+y+2=2x \n" ); document.write( ".. \n" ); document.write( "x-1=2(y-1) \n" ); document.write( "x+y+2=2x \n" ); document.write( ".. \n" ); document.write( "x-1=2y-2 \n" ); document.write( "x+y+2=2x \n" ); document.write( ".. \n" ); document.write( "x-2y=-1 \n" ); document.write( "x-y=2 \n" ); document.write( "-y=-3 \n" ); document.write( "y=3 \n" ); document.write( "x=2+y=5 \n" ); document.write( "x+y=8 \n" ); document.write( "tommy's present age=5 \n" ); document.write( "bobby's present age=3 \n" ); document.write( "billy's present age=8 \n" ); document.write( " \n" ); document.write( " |