document.write( "Question 66574This question is from textbook
\n" ); document.write( ": a lab technician has one solution that is 60% chlorinated and another that is 40% chlorinated. how much of each solution is needed to make a 100 L solution that is 50% clorine? \n" ); document.write( "
Algebra.Com's Answer #47210 by stanbon(75887)\"\" \"About 
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a lab technician has one solution that is 60% chlorinated and another that is 40% chlorinated. how much of each solution is needed to make a 100 L solution that is 50% clorine?
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\n" ); document.write( "60% solution DATA:
\n" ); document.write( "Amount is \"x\" L ; amount of chlorine in them is 0.6x L
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\n" ); document.write( "40% solution DATA:
\n" ); document.write( "Amount is \"100-x\" L ; amount of chlorine in them is 0.4(100-x)=(40-0.4x) L
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\n" ); document.write( "Mixture DATA:
\n" ); document.write( "Amount is 100 L ; amount of chlorine is 0.5(100)= 50 L
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\n" ); document.write( "EQUATION:
\n" ); document.write( "chlorine + chlorine = chlorine
\n" ); document.write( "0.6x + 40-0.4x = 50
\n" ); document.write( "0.3x=10
\n" ); document.write( "x=33.3 L (amount of 60% solution in the mixture)
\n" ); document.write( "100-33.3 L = 66.7 L (amount of 40% solution in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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