document.write( "Question 774060: Two friends live 253 miles apart. they drive toward each other to meet for a weekend. The first friend drives the speed limit and it takes her two hours to meet her friend. The second friend leaves 15 minutes late, so she drives 5 miles per hour over the speed limit. What was the second friends speed? \n" ); document.write( "
Algebra.Com's Answer #472036 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Two friends live 253 miles apart.
\n" ); document.write( " they drive toward each other to meet for a weekend.
\n" ); document.write( " The first friend drives the speed limit and it takes her two hours to meet her friend.
\n" ); document.write( " The second friend leaves 15 minutes late, so she drives 5 miles per hour over the speed limit.
\n" ); document.write( " What was the second friends speed?
\n" ); document.write( ":\
\n" ); document.write( "Let s = the speed limit
\n" ); document.write( "then
\n" ); document.write( "(s+5) = 5 mph over
\n" ); document.write( ":
\n" ); document.write( "We are dealing mph; change 15 min to .25 hrs
\n" ); document.write( "2nd friend traveled 2-.25 = 1.75 hrs
\n" ); document.write( ":
\n" ); document.write( "Write a dist equation, dist = time * speed
\n" ); document.write( ":
\n" ); document.write( "1st friend dist + 2nd friend dist = 253 miles
\n" ); document.write( "2s + 1.75(s+5)= 253
\n" ); document.write( "2s + 1.75s + 8.75 = 253
\n" ); document.write( "3.75s = 253 - 8.75
\n" ); document.write( "s = 244.25/3.75
\n" ); document.write( "s = 65.13 mph
\n" ); document.write( "I'll let you find the 2nd friend's speed
\n" ); document.write( " \n" ); document.write( "
\n" );