document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=774045>Question 774045</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm suppose to simplify e raised to ln2^5 and i moved the 5 in front of the ln but i don't know how to simplify it further, is there any more simplifications that can be made </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #472022 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=472022\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have<BR>\n" );
document.write( "(1) x = e^(ln2^5)<BR>\n" );
document.write( "Take the natural logarithm of each side to get<BR>\n" );
document.write( "(2) ln(x) = (ln2^5)*ln(e)<BR>\n" );
document.write( "Since ln(e) = 1 we have<BR>\n" );
document.write( "(3) ln(x) = ln(2^5)<BR>\n" );
document.write( "Now take the inverse log of each to get<BR>\n" );
document.write( "(4) x = 2^5 or<BR>\n" );
document.write( "(5) x = 32<BR>\n" );
document.write( "Answer: e^(ln2^5) = 32 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );