document.write( "Question 774035: Solve the linear system of equations.\r
\n" ); document.write( "\n" ); document.write( "x-3y= -6
\n" ); document.write( "5x+3y= 42\r
\n" ); document.write( "\n" ); document.write( "So far I have tried;\r
\n" ); document.write( "\n" ); document.write( "y=1/-3x+2
\n" ); document.write( "5x+3y(1/-3x+2)=42\r
\n" ); document.write( "\n" ); document.write( "Not sure if that is right so far or if I am completely wrong and either way I am not sure where to go from there.\r
\n" ); document.write( "\n" ); document.write( "Help is much appreciated, thank you!
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Algebra.Com's Answer #472013 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Given, these two equations:x-3y= -6
\n" ); document.write( "5x+3y= 42\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x=-6+3y, from first equation.\r
\n" ); document.write( "\n" ); document.write( "5(3y-6)+3y=42 for second equation.\r
\n" ); document.write( "\n" ); document.write( "15y-30+3y=42
\n" ); document.write( "18y+30=42
\n" ); document.write( "18y=12
\n" ); document.write( "\"18y%2F6=12%2F6\"
\n" ); document.write( "3y=2
\n" ); document.write( "\"y=2%2F3\"
\n" ); document.write( "You can now, having found y, find x.
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