document.write( "Question 773994: if A+B=90;SinA=3/4 then secB=? \n" ); document.write( "

Algebra.Com's Answer #471998 by Edwin McCravy(20059) $\"\"$ $\"About$

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if A+B=90;SinA=3/4 then secB=?
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document.write( "Since sine = , draw a right triangle\r\n" );
document.write( "with opposite side the numerator of 3/4, which is 3, and \r\n" );
document.write( "a hypotenuse which is the denominator of 3/4, which is 4:\r\n" );
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document.write( "A simpler way to do it is this way: \r\n" );
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document.write( "sin(A) = cos(B) = 3/4, and sec(B) = [reciprocal of cos(B)] = 4/3\r\n" );
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document.write( "{Edwin

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