document.write( "Question 772865: H and F got married 21 ye ago F was 3 times older then H today F is only twice as old how old was H 21 ye ago \n" ); document.write( "
Algebra.Com's Answer #471972 by Cromlix(4381)\"\" \"About 
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21 years ago F was 3 times older then H
\n" ); document.write( "F = 3H
\n" ); document.write( "Today F is only twice as old as H
\n" ); document.write( "F + 21 = 2(H + 21)
\n" ); document.write( "Replace F with 3H
\n" ); document.write( "3H + 21 = 2(H + 21)
\n" ); document.write( "3H + 21 = 2H + 42
\n" ); document.write( "3H - 2H = 42 - 21
\n" ); document.write( "H = 21 years old.
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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