document.write( "Question 772865: H and F got married 21 ye ago F was 3 times older then H today F is only twice as old how old was H 21 ye ago \n" ); document.write( "
Algebra.Com's Answer #471972 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! 21 years ago F was 3 times older then H \n" ); document.write( "F = 3H \n" ); document.write( "Today F is only twice as old as H \n" ); document.write( "F + 21 = 2(H + 21) \n" ); document.write( "Replace F with 3H \n" ); document.write( "3H + 21 = 2(H + 21) \n" ); document.write( "3H + 21 = 2H + 42 \n" ); document.write( "3H - 2H = 42 - 21 \n" ); document.write( "H = 21 years old. \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |