document.write( "Question 773946: Find the area of the triangle enclosed by the x-axis, the y-axis and the line y = 2x-6.\r
\n" ); document.write( "\n" ); document.write( "Nice and short... but confusing! I really don't get this question!!
\n" ); document.write( "Please help me!\r
\n" ); document.write( "\n" ); document.write( "Thanks!
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Algebra.Com's Answer #471956 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"graph%28150%2C300%2C-1%2C4%2C-8%2C2%2C2x-6%29\" It is a right triangle with legs (the perpendicular sides) measuring 3 units and 6 units.
\n" ); document.write( "You can take one leg as the base and the other as the height and use
\n" ); document.write( "area of a triangle = \"base%2Aheight%2F2=3%2A6%2F2=highlight%289%29\"
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\n" ); document.write( "How did I draw the line?
\n" ); document.write( "Since the x-axis (y=0) and the y-axis (x=0) are two of the sides, I knew one vertex of the triangle was at the origin.
\n" ); document.write( "I needed to know the other two vertices of the triangle, which would be the points where the line crossed the axis.
\n" ); document.write( "Those points are the x-intercept and y-intercept.
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\n" ); document.write( "\"system%28y=2x-6%2Cy=0%29\" --> \"0=2x-6\" --> \"6=2x\" --> \"x=3\" tells me one vertex is at \"system%28y=0%2Cx=3%29\", point (3,0).
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\n" ); document.write( "\"system%28y=2x-6%2Cx=0%29\" --> \"y=-6\" tells me the other vertex is at \"system%28y=-6%2Cx=0%29\", point (0,-6).
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