document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=773710>Question 773710</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 29. if the difference between the larger number and four times the smaller number is equal to 4, find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #471771 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=471771\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the bigger number be x and the smaller number be y.<BR>\n" );
document.write( "x + y = 29<BR>\n" );
document.write( "and <BR>\n" );
document.write( "x - 4y = 4<BR>\n" );
document.write( "Rewrite the first equation as x = 29 - y<BR>\n" );
document.write( "Substitute this equation into the second one to get<BR>\n" );
document.write( "29 - y - 4y = 4<BR>\n" );
document.write( "i.e. 29 - 5y =4<BR>\n" );
document.write( "Add 5y to each side of the equation<BR>\n" );
document.write( "29 - 5y + 5y = 4 + 5y<BR>\n" );
document.write( "i.e. 29 = 4 + 5y<BR>\n" );
document.write( "Subtract 4 from each side of the equation<BR>\n" );
document.write( "29 - 4 = 4 + 5y - 4<BR>\n" );
document.write( "i.e. 25 = 5y<BR>\n" );
document.write( "i.e. y = 5<BR>\n" );
document.write( "If the two numbers add to make 29 then the second number(x) must be 24.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );