document.write( "Question 66532: What is X if logvx(16)=-2
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Algebra.Com's Answer #47177 by stanbon(75887)\"\" \"About 
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What is X if logsqrt[x(16)]=-2
\n" ); document.write( " (1/2)log(16x)=-2
\n" ); document.write( "log16x=-4
\n" ); document.write( "10^-4=16x
\n" ); document.write( "x=6.25 x 10^-6
\n" ); document.write( "x=0.00000625
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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