document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=773713>Question 773713</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two complementary angles are such that twice the measure of first angle is equal to thrice the measure of the second angle. find the larger angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #471769 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=471769\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two complementary angles are such that twice the measure of first angle is equal to thrice the measure of the second angle. find the larger angle<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "x + y = 90 degrees<BR>\n" );
document.write( "2x = 3y<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Rearrange and modify:<BR>\n" );
document.write( "2x + 2y = 180<BR>\n" );
document.write( "2x - 3y = 0<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Solve for \"y\":<BR>\n" );
document.write( "5y = 180<BR>\n" );
document.write( "y = 36 degrees<BR>\n" );
document.write( "x = 90-36 = 54 degrees<BR>\n" );
document.write( "==========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=============== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );