document.write( "Question 773669: A liter of vinegar is 5% acid. How many more liters of pure acid are needed to get a mixture that is 81% acid? \n" ); document.write( "
Algebra.Com's Answer #471745 by josgarithmetic(39617)\"\" \"About 
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Data To Know First:
\n" ); document.write( "5% Vinegar is as weight/weight. Density 1.00 gram/ml.
\n" ); document.write( "Pure 100% Acetic Acid, assumed weight/weight, Density 1.049 gram/cm^3\r
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\n" ); document.write( "\n" ); document.write( "Use mass to do the main solving.
\n" ); document.write( "Letting a = grams of acetic acid (100% acid),
\n" ); document.write( "the mass of acid in the 1 liter of 5% is -------
\n" ); document.write( "\"1%2A%281.00%29%2A%281000%29\" \"L%2A%28g%2Fml%29%2A%28ml%2FL%29%7D%0D%0A=%7B%7B%7B1000\" grams, where \"g\" was an abbreviation for \"grams\"\r
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\n" ); document.write( "\n" ); document.write( "Equation first all in mass is then:
\n" ); document.write( "\"highlight%28%281000%2A0.05%2B1.00%2Aa%29%2F%281000%2Ba%29=0.81%29\"
\n" ); document.write( "Note that the 1.00 in the rational equation stands for \"100%\" for \"a\".\r
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\n" ); document.write( "\n" ); document.write( "The algebraic steps, not shown here, will lead to .....
\n" ); document.write( "\"a=4000\" grams
\n" ); document.write( "from which you must use density to find the result in volume liters:
\n" ); document.write( "\"highlight%284000%2A%281%2F1.049%29%281%2F1000%29=3.81%29\" Liters
\n" ); document.write( "The units conversion here is \"g%2A%28cm%5E3%2Fg%29%28L%2Fcm%5E3%29=L\"
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