document.write( "Question 773669: A liter of vinegar is 5% acid. How many more liters of pure acid are needed to get a mixture that is 81% acid? \n" ); document.write( "
Algebra.Com's Answer #471745 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Data To Know First: \n" ); document.write( "5% Vinegar is as weight/weight. Density 1.00 gram/ml. \n" ); document.write( "Pure 100% Acetic Acid, assumed weight/weight, Density 1.049 gram/cm^3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use mass to do the main solving. \n" ); document.write( "Letting a = grams of acetic acid (100% acid), \n" ); document.write( "the mass of acid in the 1 liter of 5% is ------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation first all in mass is then: \n" ); document.write( " \n" ); document.write( "Note that the 1.00 in the rational equation stands for \"100%\" for \"a\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The algebraic steps, not shown here, will lead to ..... \n" ); document.write( " \n" ); document.write( "from which you must use density to find the result in volume liters: \n" ); document.write( " \n" ); document.write( "The units conversion here is |