document.write( "Question 773500: 1) the sum of the squares of 2 consecutive positive odd number is 103 greater than their product. Find the 2 numbers.\r
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document.write( "2) The product of 3 consecutive positive integers is 65 times their total sum. Find the 3 integers. \n" );
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Algebra.Com's Answer #471679 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! (1) The two numbers are as 2n+1 and 2n+3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "We use the POSITIVE solution to n. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The numbers are \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "______________________________________ \n" ); document.write( "The numbers are 9 and 11 \n" ); document.write( "______________________________________ \n" ); document.write( " |