document.write( "Question 773500: 1) the sum of the squares of 2 consecutive positive odd number is 103 greater than their product. Find the 2 numbers.\r
\n" ); document.write( "\n" ); document.write( "2) The product of 3 consecutive positive integers is 65 times their total sum. Find the 3 integers.
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Algebra.Com's Answer #471679 by josgarithmetic(39617)\"\" \"About 
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(1) The two numbers are as 2n+1 and 2n+3.\r
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\n" ); document.write( "\n" ); document.write( "\"%282n%2B1%29%5E2%2B%282n%2B3%29%5E2=103%2B%282n%2B1%29%282n%2B3%29\"
\n" ); document.write( "\"4n%5E2%2B4n%2B1%2B4n%5E2%2B12n%2B9=103%2B4n%5E2%2B8n%2B3\"
\n" ); document.write( "\"8n%5E2%2B16%2B10=4n%5E2%2B8n%2B106\"
\n" ); document.write( "\"4n%5E2%2B8n-96=0\"
\n" ); document.write( "\"n%5E2%2B2n-24=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28n-4%29%28n%2B6%29=0\"
\n" ); document.write( "We use the POSITIVE solution to n.
\n" ); document.write( "\"n=4\".\r
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\n" ); document.write( "\n" ); document.write( "The numbers are \"2%2A4%2B1=9\"
\n" ); document.write( "and
\n" ); document.write( "\"2%2A4%2B3=11\"
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\n" ); document.write( "The numbers are 9 and 11
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