document.write( "Question 773353: Given a perimeter,P what is the largest area can you make for a quadrilateral? Express the area, A in terms of P. What kind of quadrilateral is this?
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Algebra.Com's Answer #471664 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
The question should be \"what is the largest area can you make for a \"highlight%28rectangle%29\"?\"
\n" ); document.write( "It is a much more difficult geometry/trigonometry problem if you have to prove that the largest area requires the quadrilateral to have 4 right angles.
\n" ); document.write( "(If you had to prove that it has 4 right angles, ask again. If you do it as a thank you, I'll answer it myself).
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\n" ); document.write( "WARNING: I write a lot of explanations, extra information and comments (added for better understanding), and alternate ways to get to solutions. What follows is not a streamlined solution in the format of your teacher's preference.
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\n" ); document.write( "A rectangle has two parallel sides of length \"x\", across from each other.
\n" ); document.write( "The other two sides, are perpendicular to the first two sides, and have length \"y\". We do not care if \"x\" is greater, equal or less than \"y\". It is a rectangle anyway.
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\n" ); document.write( "The perimeter of the rectangle is calculated as
\n" ); document.write( "\"P=2%28x%2By%29\"
\n" ); document.write( "The area of the rectangle is calculated as
\n" ); document.write( "\"A=xy\"
\n" ); document.write( "\"system%28P=2%28x%2By%29%2CA=xy%29\"-->\"system%28P%2F2=%28x%2By%29%2CA=xy%29\"-->\"system%28y=P%2F2-x%2CA=xy%29\"-->\"system%28y=P%2F2-x%2CA=x%28P%2F2-x%29%29\"-->\"system%28y=P%2F2-x%2CA=%28P%2F2%29%2Ax-x%5E2%29\"
\n" ); document.write( "The quadratic function \"A=x%28P%2F2-x%29\" or \"A=%28P%2F2%29%2Ax-x%5E2%29\" has zeros at \"x=0\" and \"x=P%2F2%29\", and
\n" ); document.write( "a maximum for \"x=P%2F4\"
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\n" ); document.write( "From \"x=P%2F4\" on, I see two ways to get to an expression for \"A\" in terms of \"P\".
\n" ); document.write( "\"system%28x=P%2F4%2CA=%28P%2F2%29%2Ax-x%5E2%29\"-->\"A=%28P%2F2%29%2A%28P%2F4%29-%28P%2F4%29%5E2%29\"-->\"A=P%2F8-P%2F16%29\"-->\"highlight%28A=P%2F16%29\"
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\n" ); document.write( "\"system%28x=P%2F4%2Cy=P%2F2-x%29\"-->\"system%28x=P%2F4%2Cy=P%2F2-P%2F4%29\"-->\"system%28x=P%2F4%2Cy=P%2F4%29\" which means \"system%28x=P%2F4%2Cy=P%2F4%2CA=xy%29\"-->\"A=%28P%2F4%29%2A%28P%2F4%29\"-->\"highlight%28A=P%2F16%29\"
\n" ); document.write( "The second option also tells you that
\n" ); document.write( "\"system%28x=P%2F4%2Cy=P%2F4%29\"-->\"highlight%28x=y%29\"
\n" ); document.write( "That means that the rectangle with the greatest area is a \"highlight%28square%29\"
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\n" ); document.write( "EXTRAS AND EXPLANATIONS:
\n" ); document.write( "The graph of a quadratic function is a curve called a parabola.
\n" ); document.write( "With \"A\" graphed along the \"y\" axis, the graph for \"A=%28P%2F2%29%2Ax-x%5E2%29\" looks like this:
\n" ); document.write( "\"graph%28300%2C300%2C-0.1%2C0.9%2C-0.2%2C0.8%2C3.5x-5x%5E2%29\".
\n" ); document.write( "How do we know that the maximum (vertex of the parabola), and the axis of symmetry of the parabola are at \"x=P%2F4\"?
\n" ); document.write( "For one thing, it is obvious that \"A=%28P%2F2%29%2Ax-x%5E2\" has zeros at \"x=0\" and \"x=P%2F2%29\",
\n" ); document.write( "and knowing that the function has a vertical axis of symmetry,
\n" ); document.write( "we know that \"x\" for the axis of symmetry (and the vertex/maximum that is part of that axis) has to be exactly in the middle,
\n" ); document.write( "at \"x=%28P%2F2%2B0%29%2F2=P%2F4\". So I would say it's obvious.
\n" ); document.write( "However, if your teacher likes to see formulas, and you have to \"show your work\",
\n" ); document.write( "the axis of symmetry and maximum for quadratic function of the form \"f%28x%29=ax%5E2%2Bbx%2Bc\" or \"y=ax%5E2%2Bbx%2Bc\"
\n" ); document.write( "ias at \"x=-b%2F2a\"
\n" ); document.write( "In the case of the function \"A=%28P%2F2%29%2Ax-x%5E2\" <--> \"A=-x%5E2%2B%28P%2F2%29%2Ax%2B0\"
\n" ); document.write( "\"a=-1\", \"b=P%2F2\", and \"c=0\"
\n" ); document.write( "so the axis of symmetry and maximum are at \"x=%28p%2F2%29%2F2\" --> \"highlight%28x=P%2F4%29\"
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