document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=773540>Question 773540</A>: <I><SPAN STYLE=\"word-break: break-all;\"> IN AN ISOSCELES TRIANGLE EACH OF THE BASE ANGELS IS TWICE THE VERTICAL ANGLE. FIND ALL THE ANGELS OF A TRIANGLE. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #471642 by </B><A HREF=/tutors/aboutme.mpl?userid=ramkikk66><B>ramkikk66(644)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ramkikk66><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=471642\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the vertical angle be x<BR>\n" );
document.write( "Then each base angle = 2x<BR>\n" );
document.write( "Remember that sum of the 3 angles of the triangle = 180<BR>\n" );
document.write( "i.e. 2x + 2x + x = 180<BR>\n" );
document.write( "5x = 180<BR>\n" );
document.write( "x = 180/5 = 36 deg<BR>\n" );
document.write( "Vertical angle = 36 degrees<BR>\n" );
document.write( "Each base angle = 36*2 = 72 degrees.<BR>\n" );
document.write( ":)\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );