document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=773519>Question 773519</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find four consecutive odd integers such that twice the sum of the third and fourth integer exceeds three times the first by eighty-seven </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #471634 by </B><A HREF=/tutors/aboutme.mpl?userid=pakhi><B>pakhi(24)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pakhi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=pakhi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=471634\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the four consecutive odd numbers be (2n-3),(2n-1),(2n+1),(2n+3)<BR>\n" );
document.write( "So according to the condition of the problem<BR>\n" );
document.write( "   2{(2n+1)+(2n+3)} - 3(2n-3) = 87<BR>\n" );
document.write( "or 2(4n+4) - 6n + 9 = 87<BR>\n" );
document.write( "or 8n + 8 - 6n + 9 = 87<BR>\n" );
document.write( "or 2n + 17 = 87<BR>\n" );
document.write( "or 2n = 87 - 17 = 70<BR>\n" );
document.write( "or n = 70/2 = 35\r<BR>\n" );
document.write( "\n" );
document.write( "Therefore the numbers are <BR>\n" );
document.write( "2n-3 = 2*35 - 3 = 70 - 3 = 67<BR>\n" );
document.write( "2n-1 = 2*35 - 1 = 70 - 1 = 69<BR>\n" );
document.write( "2n+1 = 2*35 + 1 = 70 + 1 = 71<BR>\n" );
document.write( "2n+3 = 2*35 + 3 = 70 + 3 = 73 \r<BR>\n" );
document.write( "\n" );
document.write( "check: 2(71+73)-3*67 = 2*144-201 =288-201 = 87 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );