document.write( "Question 773433: 2x+2y= 2/3
\n" ); document.write( "y=3x-1
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Algebra.Com's Answer #471612 by Cromlix(4381)\"\" \"About 
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2x + 2y = 2/3...1
\n" ); document.write( "y = 3x -1....2
\n" ); document.write( "Sort out (2)
\n" ); document.write( "2x + 2y = 2/3....1
\n" ); document.write( "-3x + y = -1....2
\n" ); document.write( "Multiply (1) by 3
\n" ); document.write( "Multiply (2) by 2
\n" ); document.write( "6x + 6y = 2...3
\n" ); document.write( "-6x + 2y = -2...4
\n" ); document.write( "Add (3) + (4)
\n" ); document.write( "8y = 0
\n" ); document.write( "y = 0
\n" ); document.write( "Substitute y = 0 in
\n" ); document.write( "equation (2)
\n" ); document.write( "-3x + y = -1
\n" ); document.write( "-3x + 0 = -1
\n" ); document.write( "-3x = -1
\n" ); document.write( "x = 1/3
\n" ); document.write( "x = 1/3 and y = 0
\n" ); document.write( "Hope this helps.
\n" ); document.write( ";-) \n" ); document.write( "
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