document.write( "Question 773510: kayla is twice as old as her sister, jenna. four years ago kayla was 3 times jennas age. how old is jenna now? \n" ); document.write( "
Algebra.Com's Answer #471608 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! kayla is twice as old as her sister, jenna. \n" ); document.write( "K = 2J \n" ); document.write( "four years ago kayla was 3 times jenna's age \n" ); document.write( "K - 4 = 3(J - 4) \n" ); document.write( "Replace K with 2J. \n" ); document.write( "2J - 4 = 3(J - 4) \n" ); document.write( "2J - 4 = 3J - 12 \n" ); document.write( "Collect like terms. \n" ); document.write( "2J - 3J = - 12 + 4 \n" ); document.write( "-J = -8 \n" ); document.write( "J = 8 \n" ); document.write( "Jenna is 8 years old \n" ); document.write( "Kayla is 16 years old. \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |