document.write( "Question 773510: kayla is twice as old as her sister, jenna. four years ago kayla was 3 times jennas age. how old is jenna now? \n" ); document.write( "
Algebra.Com's Answer #471608 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
kayla is twice as old as her sister, jenna.
\n" ); document.write( "K = 2J
\n" ); document.write( "four years ago kayla was 3 times jenna's age
\n" ); document.write( "K - 4 = 3(J - 4)
\n" ); document.write( "Replace K with 2J.
\n" ); document.write( "2J - 4 = 3(J - 4)
\n" ); document.write( "2J - 4 = 3J - 12
\n" ); document.write( "Collect like terms.
\n" ); document.write( "2J - 3J = - 12 + 4
\n" ); document.write( "-J = -8
\n" ); document.write( "J = 8
\n" ); document.write( "Jenna is 8 years old
\n" ); document.write( "Kayla is 16 years old.
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
\n" ); document.write( "
\n" );