document.write( "Question 773389: \"If tangent of theta equals Y/X, then find the value of theta for the ordered pair (-3, 5), and specify in which quadrant theta lies.\"
\n" ); document.write( "I was told NOT to use a calculator, so I tried plugging in the coordinates for X and Y, but I didn't know what to do from there...help!!
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Algebra.Com's Answer #471507 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"tan%28+theta%29+=Y%2FX\"\r
\n" ); document.write( "\n" ); document.write( "he value of theta for the ordered pair (\"-3\",\"+5\")\r
\n" ); document.write( "\n" ); document.write( "\"tan%28+theta%29+=5%2F-3\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%28+theta%29+=-5%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"+theta+=-59.04\"°\r
\n" ); document.write( "\n" ); document.write( "if \"tan+%28+theta%29+=+-5%2F3\", then the terminal side of ( theta) (the angle) lies in quadrant \"II\"\r
\n" ); document.write( "\n" ); document.write( "recall:\r
\n" ); document.write( "\n" ); document.write( " Quadrant \"I\" is 0°-90°,
\n" ); document.write( "Quadrant \"II\" is 90°-180°,
\n" ); document.write( "Quadrant \"III\" is 180°-270°, and
\n" ); document.write( "Quadrant \"IV\" is 270°-360°\r
\n" ); document.write( "\n" ); document.write( "0 -90 degrees is the \"positive\" x-axis and the \"positive\" y-axis
\n" ); document.write( "90-180 degrees is the \"negative\" x-axis and the \"positive\" y-axis
\n" ); document.write( " 180- 270 degrees is the \"negative\" x-axis and the \"negative\" y-axis
\n" ); document.write( "360 degrees, of course, is full circle and again the \"positive\" x-axis (like 0 degrees) and the \"negative\" y-axis\r
\n" ); document.write( "\n" ); document.write( "since given (\"-3\",\"+5\"), you know that \"x\" is negative and \"y\", your answer is Quadrant \"II\"\r
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