document.write( "Question 66497This question is from textbook Advanced mathematics
\n" ); document.write( ": Five workers can do 7 jobs in 3 days. How many days will it take 10 workers to do 14 jobs? \n" ); document.write( "
Algebra.Com's Answer #47149 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Five workers can do 7 jobs in 3 days. How many days will it take 10 workers to do 14 jobs?
\n" ); document.write( ":
\n" ); document.write( "Can we look at it this way? It takes (5*3) = 15 man/days to do 7 jobs
\n" ); document.write( ":
\n" ); document.write( "Let x = number of days to do 14 jobs; 10x man/days to do 14 jobs
\n" ); document.write( ":
\n" ); document.write( "\"%2810x%29%2F15\" = \"14%2F7\"
\n" ); document.write( ":
\n" ); document.write( "Cross multiply:
\n" ); document.write( "7(10x) = 15*14
\n" ); document.write( "70x = 210
\n" ); document.write( "x = 210/70
\n" ); document.write( "x = 3 days
\n" ); document.write( ":
\n" ); document.write( "10 men for 3 days = 30 man/days
\n" ); document.write( ":
\n" ); document.write( "Check, using man/days per job: 15/7 = 2.142857 per job
\n" ); document.write( "14 jobs would require: 2.142857*14 = 30 man/days
\n" ); document.write( "
\n" ); document.write( "
\n" );