document.write( "Question 773335: I have been trying to turn this word problem into a linear equation for a while and have had no luck. Can someone please help?
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\n" ); document.write( " A downtown employee is looking for the best option for parking a car during a 5 day work week. Garage A offers unlimited parking at a flat rate $150.00 per month. Garage B offers an hourly rate of $2.00 for parking. Which option is best for the employee on a monthly basis? \r
\n" ); document.write( "\n" ); document.write( "The employee plans on parking in the garage 5 days a week for 8 hours a day. He will be parking 160 hours per month. This is a word problem that I had to come up with on my own make 2 linear equations out of it and then graph it and show where they intercept. \r
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Algebra.Com's Answer #471479 by ramkikk66(644) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Let the parking hours be x per month, and the fee be y.\r\n" );
document.write( "In the first case, fee is fixed and not dependent on number of hours.\r\n" );
document.write( "i.e. y is independent of x. The equation in this case is y = 150.\r\n" );
document.write( "In the second case, the fee is $2 per hour. Or the equation is y = 2*x.\r\n" );
document.write( "Taking the two equations\r\n" );
document.write( " ----> (1)\r\n" );
document.write( " ----> (2)\r\n" );
document.write( "They intersect at a point where 2*x = 150 or x = 75.\r\n" );
document.write( "Obviously, if the parking hours > 75, he has to pay a fee of more than the flat\r\n" );
document.write( "fee of 150. Since he needs 160 hours of parking per month, the first option of\r\n" );
document.write( "$150 is clearly better. Option 2 is better only if he is parking for < 75 hours\r\n" );
document.write( "per month.\r\n" );
document.write( "Hope you got it :) See the graph below.\r\n" );
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