document.write( "Question 773348: 21 gram mixture of water and potassium is .8% potassium. How much water must be evaporated so that the mixture is 1.4% potassium? \n" ); document.write( "
Algebra.Com's Answer #471472 by Cromlix(4381)\"\" \"About 
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To find initial amount of potassium
\n" ); document.write( "x/21 * 100 = 0.8
\n" ); document.write( "x = 21 * 0.8/100
\n" ); document.write( "x = 0.168g
\n" ); document.write( "To find quantity of water
\n" ); document.write( "required to be evaporated to
\n" ); document.write( "attain 1.4% K
\n" ); document.write( "0.168/x * 100 = 1.4
\n" ); document.write( "1.4/100 = 0.168/x
\n" ); document.write( "Cross multiply.
\n" ); document.write( "x = 100 * 0.168/1.4
\n" ); document.write( "x = 12g
\n" ); document.write( "Therefore 9g of water must be evaporated.
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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